A Poincaré inequality for the Laplace distribution
Lately, I’ve been reading and working through Boucheron, Lugosi, and Massart’s Concentration Inequalities: A Nonasymptotic Theory of Independence. The book is (very) well written, self-contained, and full of lots of useful tools (i.e., theorems, lemmas, corollaries, and the like), as well as many thought provoking examples and exercises.
In this post, we’re going to work through a problem from Chapter 3, which is titled Bounding the Variance, that proves a Poincaré-type inequality.
The problem
Suppose we have a random variable , with a density given by
Assume that we have a differentiable function that has finite variance, i.e., . We’re going to prove that
where is the derivative of .
The proof
First, take a moment to appreciate what this result says: the variance of the function of a relatively heavy-tailed distribution is controlled by its expected value; in other words, the tails of don’t lead to wild behavior of . That’s cool!
We’ll use the following (integration by parts) fact in the proof:
where is the function that returns -1 when its argument is negative and +1 when its argument is positive.
Now we compare the third and fifth lines and note that
Finally, we chain everything together and we complete the proof:
Tips and tricks.
- In (a) we used that the variance of a random variable is not changed when a constant is added to the random variable, i.e., when we translate it.
- In (b) we used that .
- In (c) we used the integration by parts fact.
- In (d) we used the Cauchy-Schwarz inequality.
References
This post is based on material from:
- Concentration Inequalities: A Nonasymptotic Theory of Independence by S. Boucheron, G. Lugosi, and P. Masart.